UART Transmitter Figure 2 60 Mahesh Giri & P. Shingare UART Receiver Figure 3 FIFO Figure 4 Topmodule Figure 5 Design and Implementation of UART Using VHDL on FPGA 61 Schematic Results Figure 6 Figure 7 Synthesis Report Figure 8 62 Mahesh Giri & P. Shingare Total percentage of the device (spartan 3-an) resources utilized to implement our. Vhdl Code For Serial Data Transmitter And Receiver. 1/11/2018 0 Comments. The FPGA based Transmitter/Receiver data using serial. Transmitter and receiver using VHDL code. Serial Port, RS-232 Interface Code in both. Data correctly, the transmitter and receiver must. VHDL Implementation: VHDL Receiver. 42 45 receiver asynchronous vhdl code for receiver. Specifically, it provides the computer with the RS-232C Data Terminal Equipment (DTE) interface so that it can 'talk' to and exchange data with modems and other serial devices. As part of this interface. Functionality of the UART is discussed. To obtain the VHDL (or Verilog) source code described in this document, go to section VHDL (or Verilog) Code Download, page 3 for instructions. Introduction The Universal Asynchronous Receiver Transmitter (UART) is the most widely used serial data communication circuit ever. Vhdl code for serial transmitter datasheet in pdf format supplied by Datasheet Archive.
I'm trying to write RS232 transmitter module in vhdl for Spartan. According to simulation in Xilinx, it seems to be working fine, but when i try to deploy it on device, it simply doesn't work. I have found out that it might be problem with latches, but somehow I'm not able to pinpoint them. I'm using 50 Mhz clock and the bit rate of transmission is 115200 bs.
This is my vhdl code:
During synthesis I get two latch warnings:
I tried to eliminate them by adding additional if statements, but nothing seems to work.I will be grateful for any help,Ghaad
4 Answers
A process describing a register should have exactly one signal in the sensitivity list, clk (possibly a reset signal as well if you use asynchronous resets), since a register is only sensitive to a single event, namely a clock edge.
Thus your process sensitivity list baud_clock: process (clk,ready) and shiftregister : process (baud_clk, state) already indicate that you have a problem.
When describing a register, always make sure that your if(rising_edge(clk)) surrounds ALL of the described logic. A simple registered process should look like this:
Look at your 'shiftstate' process, which is responsible for driving 'ready'. How does it drive 'ready' when 'reset' is not 1, and 'start' is not 1? You haven't told it, so it keeps 'ready' unchanged in those cases. That's what 'latch' means: the process needs to remember what 'ready' was before, and keep it the same; your code therefore infers a memory. Make sure that 'ready' is driven in all branches; you can do this easily with a default assignment at the top.
Having said that, your code has multiple other issues. Did someone suggest in another thread that you shouldn't have your rising edge detection inside an if statement? Or was that someone else? Go back and read it again.
EMLEMLTry to fill all the posibilities of if statements so that for every run the program will know which value correspond to a variable. If statement has almost always go with else or elsif options to not produce latches.
A latch can occur when a process is allowed to go from start to finish without the driven outputs being assigned a value. That is if you have any conditional statements in your process and your outputs are driven inside these conditional statements then there a high chance that the outputs may never be driven. To avoid this it is good practice to place a concurrent statement at the beginning of your process to ensure your outputs are being set at least once. This will tell your synthesiser not to create a latch.
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the code is for a parallel to serial transmitter that have reset ,go clk and sout
here is the code but it give me errors
Improper array length (1). Expected length is 11.
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Error: COMP96_0083: proj22.vhd : (28, 9): The type of a choice expression does not match the case expression.
Error: COMP96_0301: proj22.vhd : (26, 3): The choice 'others' must be present when all alternatives are not covered.
Matthew Taylor
1 Answer
Improper array length (1). Expected length is 11.
Error: COMP96_0083: proj22.vhd : (28, 9): The type of a choice expression does not match the case expression.
VHDL is a strongly typed language. clk_counter is 12 bits wide. It must be compared with something at is (a) a compatible literal (a hard-coded value) and (b) has the same width. '1' is (a) a string and (b) the wrong width. You must use binary strings for a std_logic_vector and the width must match, eg:
Error: COMP96_0301: proj22.vhd : (26, 3): The choice 'others' must be present when all alternatives are not covered.
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In VHDL case statements must be complete - there must be no choices missing. Usually, there will be some choices not covered by the banches; these can be covered by adding an 'others' branch. (To be frank, the error message pretty much tells you this, which might also explain all your downvotes), eg: